The Magic of the Holiday Season: Let Us Take Care of Your Statistics Homework While You Enjoy Christmas
As the holiday season wraps Europe and America in its cozy embrace, many students are finding themselves caught between the joy of Christmas celebrations and the pressures of completing assignments. It’s a time of the year when you deserve a break, but the looming deadlines make it hard to fully relax. Whether you're wrapping presents, spending time with loved ones, or simply enjoying the festive spirit, the last thing you want to worry about is your statistics homework.
This holiday season, statistics homework help at https://www.statisticshomeworkhelper.com/ is here to ensure that you can take a step back, relax, and focus on what matters most. Our expert team is ready to handle your assignments while you enjoy the magic of Christmas. In this blog, we’ll take you through a master-level statistics question and solution, demonstrating the expertise and efficiency of our services. We’ve got your back, so you don’t have to worry about falling behind during the holiday rush.
Master-Level Statistics Assignment Question
Question:
A company manufactures light bulbs, and they claim that their bulbs have a mean lifetime of 1500 hours with a standard deviation of 100 hours. A quality control ****yst decides to test this claim by taking a sample of 40 light bulbs. After testing the sample, the ****yst finds that the sample mean lifetime is 1475 hours.
1. Set up the hypotheses to test whether the company’s claim about the mean lifetime of the bulbs is valid.
2. Perform the hypothesis test at a significance level of 0.05.
3. What is the conclusion of the hypothesis test?
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Solution:
Let’s break this down step-by-step:
Step 1: State the Hypotheses
To begin the hypothesis test, we need to set up the null and alternative hypotheses.
• Null Hypothesis (H₀): The mean lifetime of the light bulbs is equal to 1500 hours.
H0:μ=1500H₀: \mu = 1500
• Alternative Hypothesis (H₁): The mean lifetime of the light bulbs is not equal to 1500 hours.
H1:μ≠1500H₁: \mu
eq 1500
This is a two-tailed test because we are testing whether the sample mean is different from the claimed mean in either direction.
Step 2: Test Statistic and Calculation
Next, we will calculate the test statistic using the formula for the Z-test for a population mean:
Z=Xˉ−μ0σnZ = \frac{\bar{X} - \mu_0}{\frac{\sigma}{\sqrt{n}}}
Where:
• Xˉ\bar{X} = sample mean = 1475 hours
• μ0\mu_0 = population mean (claim) = 1500 hours
• σ\sigma = population standard deviation = 100 hours
• nn = sample size = 40
Now, let’s plug in the values:
Z=1475−150010040Z = \frac{1475 - 1500}{\frac{100}{\sqrt{40}}} Z=−251006.32=−2515.81=−1.58Z = \frac{-25}{\frac{100}{6.32}} = \frac{-25}{15.81} = -1.58
Step 3: Critical Value and Decision
For a significance level (α\alpha) of 0.05 in a two-tailed test, the critical Z-values are ±1.96. This means that if the calculated Z-value falls outside the range of -1.96 to 1.96, we reject the null hypothesis.
• Calculated Z-value: -1.58
• Critical values: -1.96 and 1.96
Since the calculated Z-value of -1.58 is within the range of -1.96 and 1.96, we fail to reject the null hypothesis.
Step 4: Conclusion
Based on our test, there is insufficient evidence to reject the company’s claim that the mean lifetime of the light bulbs is 1500 hours. Therefore, we conclude that the mean lifetime is indeed 1500 hours, and the company’s claim holds.
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