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🔍 Question:
Given a slice of integers, write a function that returns the maximum sum of a contiguous subarray within the slice.
Example:
Input: [-2, 1, -3, 4, -1, 2, 1, -5, 4]
Output: 6 (Explanation: The contiguous subarray [4, -1, 2, 1] has the largest sum of 6.)
🔧 Solution:
package main
import "fmt"
func maxSubarraySum(nums []int) int {
maxSum := nums[0] // Initialize maxSum as the first element of the slice
currentSum := maxSum
for i := 1; i < len(nums); i++ {
currentSum = max (nums[i], currentSum+nums[i]) // Update currentSum to be the maximum of the current element or the sum of the current element and the previous sum
maxSum = max (maxSum, currentSum) // Update maxSum to be the maximum of maxSum and currentSum
}
return maxSum
}
func max (a, b int) int {
if a > b {
return a
}
return b
}
func main() {
nums := []int{-2, 1, -3, 4, -1, 2, 1, -5, 4}
fmt.Println("Maximum sum of a contiguous subarray:", maxSubarraySum(nums))
}
💡 Explanation:
- > We initialize two variables, maxSum and currentSum, to the first element of the slice.
- > We iterate through the slice, updating currentSum to be the maximum of the current element or the sum of the current element and the previous sum.
- > We update maxSum to be the maximum of maxSum and currentSum.
- > Finally, we return maxSum, which holds the maximum sum of a contiguous subarray within the slice.
🎉 Voila! You've just learned how to find the maximum sum of a contiguous subarray in GoLang. Need more assistance with your GoLang assignments? Visit at https://www.programminghomeworkhelp.com/golang/ for expert help!
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